FAU Erlangen-Nürnberg
Part I — Formalism (postulates completed)
Part II — Solvable models & many electrons
A Hermitian operator \(\hat{A}\) has eigenstates \(|\phi_{A_n}\rangle\) with eigenvalues \(A_n\):
\[\hat{A}\,|\phi_{A_n}\rangle = A_n\,|\phi_{A_n}\rangle\]
The eigenstates form an orthonormal basis of the Hilbert space:
\[\langle \phi_{A_m} | \phi_{A_n} \rangle = \delta_{mn}\]
Any quantum state \(|\psi\rangle\) admits the expansion
\[|\psi\rangle = \sum_n c_n\, |\phi_{A_n}\rangle, \qquad c_n = \langle \phi_{A_n} | \psi \rangle\]
The expansion coefficients carry probabilistic meaning:
\[P(A_n) = |c_n|^2\]
— consistent with Postulate 4.
This is the orthogonal (or spectral) decomposition of \(|\psi\rangle\).
Note
The orthogonal decomposition is the bridge between abstract Hilbert-space states and concrete measurement statistics.
Measurement does not just report an eigenvalue — it changes the state.
If a measurement of \(\hat{A}\) yields the eigenvalue \(a_n\), the post-measurement state is the corresponding eigenstate:
\[|\psi\rangle \;\longrightarrow\; |\phi_{a_n}\rangle\]
Often called wavefunction collapse or projection postulate:
\[|\psi\rangle \;\longrightarrow\; \frac{\hat{P}_n |\psi\rangle}{\| \hat{P}_n |\psi\rangle \|}, \qquad \hat{P}_n = |\phi_{a_n}\rangle\langle\phi_{a_n}|\]
Repeating the same measurement immediately reproduces \(a_n\) with probability \(1\).
For \(N\) classical particles, total energy = kinetic + potential:
\[E = E_{\rm kin} + V = \sum_{j=1}^{N} \frac{p_j^2}{2 m_j} + V\]
The correspondence principle promotes this to a quantum operator:
\[\hat{H} = \sum_{j=1}^{N} \frac{\hat{p}_j^{\,2}}{2 m_j} + V(t,\hat{\mathbf{x}}_1,\ldots,\hat{\mathbf{x}}_N)\]
The energy eigenvalue problem reads
\[\hat{H}\,|\phi_n\rangle = E_n\,|\phi_n\rangle\]
Substitute \(\hat{p}_j = -i\hbar\,\nabla_j\) to obtain the position-space Hamiltonian:
\[\hat{H}(t, \mathbf{x}_1,\ldots,\mathbf{x}_N) = -\sum_{j=1}^{N} \frac{\hbar^2}{2 m_j}\,\Delta_j + V(t, \mathbf{x}_1,\ldots,\mathbf{x}_N)\]
The stationary Schrödinger equation becomes a partial differential equation:
\[\left(-\sum_{j=1}^{N} \frac{\hbar^2}{2 m_j}\,\Delta_j + V(t, \mathbf{x}_1,\ldots,\mathbf{x}_N)\right)\psi = E\,\psi\]
For time-independent \(V\), this is the stationary Schrödinger equation; eigenfunctions \(\phi_n\) are stationary states.
The full state evolves according to the time-dependent Schrödinger equation:
\[i\hbar\,\frac{\partial}{\partial t}|\psi(t)\rangle = \hat{H}\,|\psi(t)\rangle\]
For time-independent \(\hat{H}\), separate \(|\psi(t)\rangle = |\psi_t(t)\rangle\,|\psi_x\rangle\):
\[\frac{\partial |\psi_t\rangle}{\partial t} = -i\,\frac{E}{\hbar}\,|\psi_t\rangle \quad\Rightarrow\quad |\psi_t(t)\rangle = C\,e^{-iEt/\hbar}\]
Energy eigenstates evolve only by a phase:
\[|\psi(t)\rangle = \sum_n c_n\,e^{-i E_n t/\hbar}\,|\phi_n\rangle\]
If \(|\psi_1\rangle, |\psi_2\rangle, \ldots, |\psi_K\rangle\) solve the Schrödinger equation, so does
\[|\psi\rangle = \sum_{j=1}^{K} c_j\,|\psi_j\rangle, \qquad c_j \in \mathbb{C}\]
Note
Energy eigenstates are convenient because they propagate by simple phase factors \(e^{-iE_n t/\hbar}\) — but any complete orthonormal basis works.
\[s = \tfrac{1}{2}, \qquad m_s = \pm\tfrac{1}{2}\]
Two spin states, denoted \(|\alpha\rangle\) (“spin up”) and \(|\beta\rangle\) (“spin down”).
Spin- \(\tfrac{1}{2}\) operators in the \(|\alpha\rangle, |\beta\rangle\) basis:
\[\hat{S}_x = \tfrac{\hbar}{2}\sigma_x,\quad \hat{S}_y = \tfrac{\hbar}{2}\sigma_y,\quad \hat{S}_z = \tfrac{\hbar}{2}\sigma_z\]
Pauli matrices:
\[\sigma_x = \begin{pmatrix}0 & 1\\ 1 & 0\end{pmatrix},\;\; \sigma_y = \begin{pmatrix}0 & -i\\ i & 0\end{pmatrix},\;\; \sigma_z = \begin{pmatrix}1 & 0\\ 0 & -1\end{pmatrix}\]
\(\hat{S}_z\) eigenstates: \(\hat{S}_z|\alpha\rangle = +\tfrac{\hbar}{2}|\alpha\rangle\), \(\hat{S}_z|\beta\rangle = -\tfrac{\hbar}{2}|\beta\rangle\).
The components do not commute: \([\hat{S}_x,\hat{S}_y] = i\hbar\,\hat{S}_z\) — only one component is sharp at a time.
The full electronic wavefunction is a tensor product of a spatial and a spin part:
\[\psi = \psi_x(\mathbf{r})\,\chi(s)\]
Common shorthand for one-electron spin-orbitals:
\[\phi(\mathbf{r}, s) = \psi_x(\mathbf{r})\,|\alpha\rangle \quad \text{or} \quad \psi_x(\mathbf{r})\,|\beta\rangle\]
Quantum mechanics is probabilistic — we summarise outcomes statistically.
For an observable \(\hat{A}\) in state \(|\psi\rangle\), the expectation value is
\[\langle \hat{A}\rangle = \langle \psi | \hat{A} | \psi\rangle = \sum_n A_n\,P(A_n)\]
The variance measures the spread:
\[\text{Var}(\hat{A}) = \langle \hat{A}^2\rangle - \langle \hat{A}\rangle^2\]
For energy: \(\langle \hat{H}\rangle\) is the energy expectation; eigenstates have zero variance.
Suppose \(|\psi\rangle\) is any normalized state, \(\langle\psi|\psi\rangle = 1\).
Decompose into eigenstates of \(\hat{H}\):
\[|\psi\rangle = \sum_n c_n\,|\phi_{H_n}\rangle\]
Compute the energy expectation:
\[\langle\psi|\hat{H}|\psi\rangle = \sum_n E_n\,|c_n|^2 = \sum_n E_n\,P(E_n)\]
Since \(E_0 \le E_n\) for all \(n\):
\[\langle\psi|\hat{H}|\psi\rangle = \sum_n E_n\,P(E_n) \;\ge\; E_0 \sum_n P(E_n) = E_0\]
Note
Variational principle. For any normalized trial state \(|\psi\rangle\),
\[\langle \psi|\hat{H}|\psi\rangle \;\ge\; E_0.\]
Equality iff \(|\psi\rangle\) is the ground state.
For unnormalised trial states, use the Rayleigh quotient:
\[\frac{\langle\psi|\hat{H}|\psi\rangle}{\langle\psi|\psi\rangle} \;\ge\; E_0\]
Pick a trial wavefunction \(|\psi_{\text{trial}}(\alpha)\rangle\) depending on parameters \(\alpha\), then minimise:
\[\frac{\partial}{\partial \alpha}\!\left(\frac{\langle\psi_{\text{trial}}|\hat{H}|\psi_{\text{trial}}\rangle}{\langle\psi_{\text{trial}}|\psi_{\text{trial}}\rangle}\right) = 0\]
When \(\hat{H}\) cannot be solved exactly, decompose into a solvable part plus a small correction:
\[\hat{H} = \hat{H}_0 + \epsilon\,\hat{H}_1\]
Expand both energies and states in powers of \(\epsilon\):
\[E_n = \sum_{j=0}^{\infty}\epsilon^{j}\,E_n^{(j)}, \qquad |\psi_n\rangle = \sum_{j=0}^{\infty}\epsilon^{j}\,|\psi_n^{(j)}\rangle\]
Insert into \(\hat{H}|\psi_n\rangle = E_n|\psi_n\rangle\) and collect powers of \(\epsilon\):
\[\epsilon^0:\quad \hat{H}_0|\psi_n^{(0)}\rangle = E_n^{(0)}|\psi_n^{(0)}\rangle\]
\[\epsilon^1:\quad \hat{H}_0|\psi_n^{(1)}\rangle + \hat{H}_1|\psi_n^{(0)}\rangle = E_n^{(0)}|\psi_n^{(1)}\rangle + E_n^{(1)}|\psi_n^{(0)}\rangle\]
Project onto \(\langle\psi_n^{(0)}|\) and use \(\langle\psi_n^{(0)}|\hat{H}_0 = \langle\psi_n^{(0)}|E_n^{(0)}\) to obtain:
\[\boxed{\;E_n^{(1)} = \langle\psi_n^{(0)}|\hat{H}_1|\psi_n^{(0)}\rangle\;}\]
— the first-order energy correction is just the expectation of the perturbation in the unperturbed state.
The standard form is stationary Rayleigh-Schrödinger perturbation theory.
For time-dependent perturbations (transitions, optical absorption) one uses Dirac (time-dependent) perturbation theory — beyond this lecture.
Set \(V(x) = 0\). The 1D Schrödinger equation reads
\[-\frac{\hbar^2}{2m}\frac{d^2\psi}{dx^2} = E\,\psi\]
Solutions are plane waves with continuous wavevector \(k\in\mathbb{R}\):
\[\psi_k(x) = \frac{1}{\sqrt{2\pi}}\,e^{ikx}, \qquad E = \frac{\hbar^2 k^2}{2m} \ge 0\]
The spectrum is continuous and non-negative — a sharp contrast to bound states.
\[\langle\psi_k|\psi_k\rangle = \int_{-\infty}^{\infty}\frac{1}{2\pi}\,dx \;\to\; \infty\]
\[\psi(x,t) = \int dk\; \tilde\psi(k)\,e^{i(kx - \omega(k)\,t)}, \qquad \omega(k) = \frac{\hbar k^2}{2m}\]
Wave packets disperse — the group velocity gives the classical particle velocity.
Potential of a quadratic restoring force:
\[V(x) = \tfrac{1}{2}k\,x^2 = \tfrac{1}{2}m\omega^2 x^2, \qquad \omega = \sqrt{k/m}\]
The spectrum is equidistant with quantum number \(n = 0,1,2,\ldots\):
\[E_n = \hbar\omega\!\left(n + \tfrac{1}{2}\right)\]
The eigenfunctions involve Hermite polynomials \(H_n\):
\[\psi_n^{\rm harm}(x;m,\omega) = \frac{1}{\sqrt{2^n n!}}\!\left(\frac{m\omega}{\pi\hbar}\right)^{1/4}\!H_n\!\left(\sqrt{\tfrac{m\omega}{\hbar}}\,x\right)\exp\!\left(-\tfrac{m\omega}{2\hbar}x^2\right)\]
\[H_n(x) = (-1)^n\,e^{x^2}\,\frac{d^n}{dx^n}\,e^{-x^2}\]
Each level alternates parity: \(H_0=1\) (even), \(H_1\propto x\) (odd), \(H_2\propto 4x^2-2\) (even), …
Define creation/annihilation operators
\[\hat{a} = \sqrt{\tfrac{m\omega}{2\hbar}}\!\left(\hat{x} + \tfrac{i}{m\omega}\hat{p}\right), \qquad \hat{a}^{\dagger} = \sqrt{\tfrac{m\omega}{2\hbar}}\!\left(\hat{x} - \tfrac{i}{m\omega}\hat{p}\right)\]
with canonical commutator \([\hat{a},\hat{a}^{\dagger}] = 1\).
Then \(\hat{H} = \hbar\omega\!\left(\hat{a}^{\dagger}\hat{a} + \tfrac{1}{2}\right)\) and
\[\hat{a}^{\dagger}|n\rangle = \sqrt{n+1}\,|n+1\rangle, \qquad \hat{a}|n\rangle = \sqrt{n}\,|n-1\rangle\]
Algebraic derivation of the spectrum without solving any ODE — same idea reused for phonons, photons and the entire formalism of second quantisation.
Note
The harmonic oscillator is arguably the most important model in physics — almost every weakly excited bosonic system reduces to it.
Separable potential
\[V(\mathbf{x}) = \frac{m}{2}\sum_{i=1}^{d}\omega_i^2\,x_i^2\]
Eigenfunctions factorise; eigenenergies sum:
\[\psi_{n_1,\ldots,n_d}(\mathbf{x}) = \prod_{i=1}^{d}\psi_{n_i}^{\rm harm}(x_i;m,\omega_i)\]
\[E = \sum_{i=1}^{d}\hbar\omega_i\!\left(n_i + \tfrac{1}{2}\right)\]
Most well-behaved separable potentials reduce similarly — the 1D building block does the heavy lifting.
A particle confined to a box:
\[V(x) = \begin{cases}0, & 0 < x < L \\ \infty, & \text{otherwise}\end{cases}\]
Boundary conditions \(\psi(0) = \psi(L) = 0\) select sine modes:
\[\psi_n(x) = \sqrt{\tfrac{2}{L}}\,\sin\!\left(\tfrac{n\pi x}{L}\right), \qquad n = 1,2,\ldots\]
Energy spectrum scales as \(n^2\):
\[E_n = \frac{n^2 \pi^2 \hbar^2}{2 m L^2}\]
The infinite well is the prototype for quantum dots, semiconductor nanowires, and “particle-in-a-box” molecular models.
A more physical bound system:
\[V(x) = \begin{cases}-V_0, & |x| < a \\ 0, & |x| \ge a\end{cases}\]
Bound states have \(-V_0 < E < 0\). Wavefunctions are oscillatory inside, exponentially decaying outside:
\[\psi(x) = \begin{cases}A\,e^{\kappa x}, & x < -a \\ B\cos(kx) + C\sin(kx), & |x| < a \\ D\,e^{-\kappa x}, & x > a\end{cases}\]
\[k = \sqrt{\tfrac{2m(E + V_0)}{\hbar^2}}, \qquad \kappa = \sqrt{\tfrac{-2mE}{\hbar^2}}\]
Matching \(\psi\) and \(\psi'\) at \(\pm a\) yields the transcendental conditions
\[k\,\tan(ka) = \kappa \quad\text{(even)}, \qquad -k\,\cot(ka) = \kappa \quad\text{(odd)}\]
Tunnelling is essential for STM, alpha decay, fusion, Josephson junctions, and chemical reaction rates.
Helium (\(Z=2\), 2 electrons): the simplest non-trivial atom. The Hamiltonian, in the nucleus’ frame, reads
\[\hat{H}_{\rm He} = -\frac{\hbar^2}{2m_e}(\Delta_{\mathbf{r}_1} + \Delta_{\mathbf{r}_2}) + \frac{e^2}{4\pi\varepsilon_0}\!\left[(-Z)\!\left(|\mathbf{r}_1|^{-1} + |\mathbf{r}_2|^{-1}\right) + |\mathbf{r}_1 - \mathbf{r}_2|^{-1}\right]\]
Note
The electron-electron repulsion \(|\mathbf{r}_1 - \mathbf{r}_2|^{-1}\) couples the two electrons. The Schrödinger equation \(\hat{H}_{\rm He}|\psi\rangle = E|\psi\rangle\) has no closed-form solution — we must approximate.
Drop the \(|\mathbf{r}_1 - \mathbf{r}_2|^{-1}\) term — the equation separates:
\[|\psi_{\rm He}(\mathbf{r}_1,\mathbf{r}_2)\rangle = |\psi_1(\mathbf{r}_1)\rangle\,|\psi_2(\mathbf{r}_2)\rangle\]
Each electron is hydrogen-like with nuclear charge \(Z\):
\[E_{n_1, n_2}^{\rm He} = E_{n_1} + E_{n_2}\]
For ground state \(n_1 = n_2 = 1\):
\[E_{1,1}^{\rm He} = -2 Z^2\,(13.6\ \text{eV}) = -108.8\ \text{eV}\]
Experimental total ionisation energy: \(-78.93\ \text{eV}\). Error \(\approx 30\ \text{eV}\) (\(\approx 40\%\)) — too large.
Refine by introducing an effective nuclear charge:
\[Z_{\rm eff} = Z - S\]
\[E_{1,1}^{\rm He} = -(1 + Z^2)(13.6\ \text{eV}) = -68.0\ \text{eV}\]
— much closer to experiment
Screening intuition shows up everywhere: Slater rules, pseudopotentials, Kohn-Sham orbitals.
The product ansatz \(|\psi_1(\mathbf{r}_1)\rangle|\psi_2(\mathbf{r}_2)\rangle\) has a conceptual flaw:
The probability density must be invariant under particle exchange:
\[|\psi(\mathbf{r}_1, \mathbf{r}_2)|^2 = |\psi(\mathbf{r}_2, \mathbf{r}_1)|^2\]
Invariance of \(|\psi|^2\) allows at most a phase under exchange:
\[\psi(\mathbf{r}_2,\mathbf{r}_1) = e^{i\alpha}\,\psi(\mathbf{r}_1,\mathbf{r}_2)\]
Applying twice must return to the original state: \(e^{2i\alpha} = 1 \;\Rightarrow\; e^{i\alpha} = \pm 1\).
For electrons:
\[\psi(\mathbf{r}_2, \mathbf{r}_1) = -\psi(\mathbf{r}_1, \mathbf{r}_2)\]
The naive product \(|\psi_a(\mathbf{r}_1)\rangle|\psi_b(\mathbf{r}_2)\rangle\) is not antisymmetric. Form
\[|\psi^-\rangle = \tfrac{1}{\sqrt{2}}\Big(|\psi_a(\mathbf{r}_1)\rangle|\psi_b(\mathbf{r}_2)\rangle - |\psi_b(\mathbf{r}_1)\rangle|\psi_a(\mathbf{r}_2)\rangle\Big)\]
Indeed \(\psi^-(\mathbf{r}_2,\mathbf{r}_1) = -\psi^-(\mathbf{r}_1,\mathbf{r}_2)\) — and \(\langle\psi^-|\psi^-\rangle = 1\).
If both electrons occupy the same spin-orbital \(\psi_a\):
\[|\psi^-\rangle = \tfrac{1}{\sqrt{2}}(|\psi_a\rangle|\psi_a\rangle - |\psi_a\rangle|\psi_a\rangle) = 0\]
— this is the Pauli exclusion principle: no two electrons share the same spin-orbital.
Nuclei at \(\mathbf{R}_i\) (\(N_{\rm at}\) total), electrons at \(\mathbf{r}_i\) (\(N_e\) total):
\[\hat{H} = \underbrace{-\sum_{i}\!\frac{\hbar^2}{2 M_i}\Delta_{\mathbf{R}_i}}_{T_{\rm nuc}}\,\underbrace{-\sum_{i}\!\frac{\hbar^2}{2 m_e}\Delta_{\mathbf{r}_i}}_{T_{\rm el}}\,\underbrace{-\frac{e^2}{4\pi\varepsilon_0}\!\sum_{i,j}\!\frac{Z_i}{|\mathbf{R}_i - \mathbf{r}_j|}}_{V_{\rm en}}\]
\[\;+\; \underbrace{\tfrac{1}{2}\frac{e^2}{4\pi\varepsilon_0}\!\sum_{i\ne j}\!\frac{1}{|\mathbf{r}_i - \mathbf{r}_j|}}_{V_{\rm ee}}\;+\;\underbrace{\tfrac{1}{2}\frac{e^2}{4\pi\varepsilon_0}\!\sum_{i\ne j}\!\frac{Z_i Z_j}{|\mathbf{R}_i - \mathbf{R}_j|}}_{V_{\rm nn}}\]
Nuclear kinetic + electron kinetic + electron-nuclear + electron-electron + nuclear-nuclear.
Mass disparity: \(M_i \gg m_e\) (\(M_{\rm proton}/m_e \approx 1836\)) \(\Rightarrow\) nuclei are much slower than electrons.
Born-Oppenheimer:
After Born-Oppenheimer, the electronic Hamiltonian is
\[\hat{H}_{\rm el} = -\sum_{i=1}^{N_e}\!\frac{\hbar^2}{2 m_e}\Delta_{\mathbf{r}_i} - \frac{e^2}{4\pi\varepsilon_0}\!\left(\sum_{i,j}\!\frac{Z_i}{|\mathbf{R}_i - \mathbf{r}_j|} + \tfrac{1}{2}\sum_{i\ne j}\!\frac{1}{|\mathbf{r}_i - \mathbf{r}_j|}\right) + V_{\rm nn}\]
Note
Most of computational materials science operates inside Born-Oppenheimer. Knowing where it fails is essential when interpreting simulations as data.
A first guess for an \(N\)-electron wavefunction: assume independence and multiply one-electron orbitals \(\phi_j\):
\[\psi(\mathbf{r}_1,\ldots,\mathbf{r}_N) = \prod_{j=1}^{N}\phi_j(\mathbf{r}_j)\]
We need a properly antisymmetric many-electron ansatz.
Build a fully antisymmetric many-electron wavefunction as a determinant of one-electron spin-orbitals:
\[\psi(\mathbf{r}_1,\ldots,\mathbf{r}_N) = \frac{1}{\sqrt{N!}}\det\!\begin{pmatrix}\phi_1(\mathbf{r}_1) & \phi_2(\mathbf{r}_1) & \cdots & \phi_N(\mathbf{r}_1)\\ \phi_1(\mathbf{r}_2) & \phi_2(\mathbf{r}_2) & \cdots & \phi_N(\mathbf{r}_2)\\ \vdots & \vdots & \ddots & \vdots\\ \phi_1(\mathbf{r}_N) & \phi_2(\mathbf{r}_N) & \cdots & \phi_N(\mathbf{r}_N)\end{pmatrix}\]
Common compact notation drops the prefactor visually using vertical bars:
\[\psi(\mathbf{r}_1,\ldots,\mathbf{r}_N) = \frac{1}{\sqrt{N!}}\begin{vmatrix}\phi_1(\mathbf{r}_1) & \cdots & \phi_N(\mathbf{r}_1)\\ \vdots & \ddots & \vdots\\ \phi_1(\mathbf{r}_N) & \cdots & \phi_N(\mathbf{r}_N)\end{vmatrix}\]
For molecules and solids, the molecular wavefunction should look “atom-like” near each nucleus.
Ansatz: expand each molecular orbital in atomic orbitals \(\psi_j^a\):
\[|\psi\rangle = \sum_{j=1}^{N_b} c_j\,|\psi_j^a\rangle = \mathbf{c}^{T}\boldsymbol{\psi}^a\]
Substitute the LCAO ansatz into the Schrödinger equation. Atomic orbitals on different atoms are generally not orthogonal \(\Rightarrow\) generalised eigenvalue problem:
\[\boxed{\;\mathbf{H}\,\mathbf{c} = E\,\mathbf{S}\,\mathbf{c}\;}\]
Reduces a PDE (infinite-dim. eigenproblem) to a finite matrix problem of size \(N_b\) — the central simplification underlying nearly all quantum-chemistry codes.

© Philipp Pelz - Materials Genomics